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Find the unknown.$$(x-4)^{2}+16=0$$

$$4 \pm 4 i$$

Algebra

Chapter 0

Reviewing the Basics

Section 2

Solving Equations of the Form $a x^{2}-b=0$

Equations and Inequalities

Campbell University

Oregon State University

Harvey Mudd College

University of Michigan - Ann Arbor

Lectures

00:56

Find the unknown.$$x^{…

02:36

Find the unknown.$$(6 …

00:47

00:58

Find the unknown.$$8 x…

00:24

Solve.$x^{2}+16=0$

00:32

00:25

Solve equation by the meth…

01:03

Solve the equations.$$…

are solving for X in this one. We're looking at Xmas for squared plus 16 is equal to zero. So what you want to do is get this squared all by itself. You can easily do that by moving the 16 over by subtracting it. Uh, and zero minus 16 is equal to negative 16. And on that left side, there's gonna leave that alone. Next one is for B squared, because our next step is to solve the square part by undoing that with the square root. Um, and for the sake of mhm of helping you out, this is a non real solution. Um, because when you square root of negative, that's saying, Hey, we need to have an imaginary answer because it's impossible for a real number of positive or negative. Once we square, it will give us a positive not a negative. Um, and then the square root of 16 is four plus or minus four I and on the left side, the square root mean square cancel. We're left with X minus four. And then to finish this problem, we solve for X by adding the forward to the right side so it becomes a positive for, you know, even show that step. But they're not like terms, so we just It's common for math people to just stick the four in front. We're looking at four plus or minus four I and there is your complex solution four plus or minus four I

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