00:01
Hi guys, let's solve problem 14.
00:04
Here is the determinant.
00:07
Here we can see that this is a triangular determinant as here is a triangle and after that here all the elements are zero.
00:21
So in this case we can evaluate this in two ways.
00:27
So here we can take the first column as it contains.
00:34
Highest number of 0 so it will be easier to calculate so let's take negative 2 negative 2 and after canceling the row and column we get this 3 by 3 matrix and rest of the items are 0 so we can write it like this but we don't need to calculate this because whatever we multiply with 0 the result will be 0 so we can cancel out these three parts.
01:04
Now, let's calculate the first part.
01:08
So here, here is a 3 by 3 matrix.
01:12
Let's calculate it.
01:14
So, the first row of this 3 by 3 matrix is here.
01:19
So the first number here is 3.
01:21
So we will write 3.
01:23
And after canceling the row and column of 3, we get this 2 by 2 matrix.
01:28
Now we will write the second number which is 0 we are considering the first column sorry we are considering the first column as it has highest number of 0 so the calculation will be smaller so here the second number is 0 so negative 0 and then after canceling the row and column we will get this 2 by 2 matrix in the same way we will take the third number 0 and cancel out the row and column to get this 2 by 2 metrics.
02:04
But here same again, we don't have to calculate these parts as it contains 0.
02:09
So whatever we multiply with 0, the result will be 0...