00:01
This problem uses kirchhoff's current law, which says that some of the currents into a node is equal to some of the currents out.
00:07
Also, kirchhoff's voltage law, which says that as we work around a closed loop, the sum of the voltage drops is equal to zero.
00:16
And finally, that current times resistance is equal to voltage.
00:22
So it uses ohm's law as well.
00:24
So first thing i'm going to do is do kerchhoff's current law at node a, there at the top of the search.
00:30
Circuit and there i have three amps going in and that's equal to i1 plus i2.
00:39
So therefore, i'll use it here in a little bit, i1 is equal to three amps minus i2.
00:49
So i'll come back to that later.
00:51
I'm going to keep that in my pocket.
00:54
Then if i look at the left -hand side over here at i -2 as it works its way around the circuit or around that branch of the circuit, then kirchhoff's voltage law tells me that minus 18 volts and now i'm working my way.
01:17
I'm counting the voltages this direction, the clockwise direction.
01:22
But the current is running in the opposite direction.
01:26
So i have minus 18 volts minus 3 kilo -ooms times i -2, minus 2, i'm sorry, that's regular oms, minus 2 -ooms times i -2...