00:01
This problem uses kirchhoff's current law.
00:03
It says that for any node, the sum of the currents in is equal to some of the currents out.
00:08
And i have those nodes lettered, a, b, c, and d.
00:12
He uses kirchhoff's voltage law.
00:14
It says for any closed loop, the sum of the voltages is equal to zero.
00:18
And i have those numbered 1, 2, 3, 4, and 5.
00:22
Has voltage is equal to current times resistance.
00:25
We're going to use oms law.
00:26
We're also going to use the definition of power, which says that it is current times voltage.
00:33
And i'll start out using that because the power that is supplied by that current source is equal to 60 watts.
00:42
And that's equal to current times voltage.
00:46
Well, i know that the current is equal to 5 amps and so therefore the voltage is 12 volts.
00:57
Now, i can turn around and use that because that is equal to the voltage drop on the other side of that branch there in 5, that loop in 5.
01:12
So that 12 volts is equal to i1 times that 2 -oom resistor.
01:23
And that means that i -1 is equal to 6 amps.
01:29
And so we are off and running...