The vertex of a parabola in the form $y=ax^2+bx+c$ is given by the coordinates $\left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)$. In this case, $a=1$, $b=1$, and $c=1$. So the x-coordinate of the vertex is $-\frac{1}{2(1)}=-\frac{1}{2}$, and the
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