00:01
Okay, so here we have the function, f of x is equal to x squared minus 2x minus 15.
00:05
And we notice here that we have a quadratic in standard form.
00:10
In the form, f of x is equal to ax squared plus bx plus c, right? well, a is 1, b, well, is a negative 2, because negative 2x is plus a negative 2x.
00:24
And then c, well, negative 15, minus 15 is plus a negative 15.
00:28
So c is minus 15.
00:31
So we know that our vertex of the parabola is going to be at the point negative b over 2a, comma, f of negative b over 2a.
00:47
Okay.
00:48
Let's just go ahead and find, well, negative b over 2a.
00:50
So we have, well, b is a negative 2.
00:54
So we have negative and negative 2.
00:57
That's just positive 2 over 2a or over 2 times 1.
01:03
Well, this is just equal to 2, right? this is minus negative 2 is just 2 over 2 times 1, which is 2.
01:10
Therefore 2 over 2 is equal to 1.
01:13
So therefore our x value of our vertex is just 1.
01:18
Okay? to find the corresponding y value, we just substitute in 1 because we're going to find f of, negative b over 2a.
01:29
Well negative b over 2a we just found to be one.
01:32
So f of negative b over 2a is just f of 1.
01:36
Well f of 1 means just substituting in 1 for x in your function.
01:42
So we have 1 squared minus 2 times 1 minus 15.
01:49
Okay.
01:49
Well that equals 1 minus 2 minus 15 is minus 16.
01:56
So f of 1 is equal to negative 16.
02:00
So therefore, that is our y value of our vertex.
02:03
So therefore, our vertex is at the point 1 comma negative 16.
02:09
Okay, so there we have our vertex.
02:11
Now, to find the x intercepts, while the x intercepts happen where the function is equal to zero.
02:19
Or where y, right, f of x is just a little name for y, really.
02:22
So when y is equal to zero, right, whatever the value of x is there, that's where we're going to intersect the x -axis.
02:31
So to find the x intercepts, you set your function equal to zero, and we have zero is equal to x squared minus 2x minus 15.
02:42
Okay.
02:42
Now, well, you can always use the quadratic equation here to solve for x, or you could just, i mean, i guess an easier way would be if you can factor, always try and factor.
02:54
And this should factor actually pretty nice.
02:56
If you try to factor this, we have zero is equal to.
02:58
If we factor x squared minus 2x minus 15, we get what? we get well, x squared has been x times x.
03:05
Now 15, well, that's three times five, and the difference of five and three is two.
03:10
So i think we're going to need a three and a five, right? i need different signs to multiply to a negative 15.
03:16
I have to add to a negative two.
03:18
So the negative better be on the larger value or the five.
03:23
So we have x plus three times.
03:26
X minus five okay that's factored now so therefore i have two factors two things being multiplied together that's equal to zero so we know that at least one of the factors must be zero so either x plus three is zero well that means that x is equal to negative three right or x minus five is zero which means that x is equal to five okay so therefore our x intercepts are going to be, well, when x is negative three, y is zero.
04:03
So we have the x intercept of negative three, zero...