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Find the volume generated by revolving the regions bounded by the given curves about the $y$ -axis. Use the indicated method in each case.$$y=\sqrt{x}, y=1, y=2, x=0 \quad \text { (disks) }$$

Calculus 2 / BC

Chapter 26

Applications of Integration

Section 3

Volumes by Integration

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Lectures

01:11

In mathematics, integratio…

06:55

In grammar, determiners ar…

01:20

Let R be the region boun…

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02:21

Find the volumes of the so…

02:18

Let R be the region bounde…

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and they give us the Y equals the square root of X. Um It should be more curvy than when I wrote. That's okay. They also give us the bounds of white goes 12 white ones too. And it's made with the Y axis at X equals zero. So that's why they give you that bound as well As you revolve. It makes perfect sense that it is the disk method. Just show one circle there Going from 1 to 2 of the function and give us squared in terms of why? Because it's around the Y axis. So I would rewrite this as X equals Y squared. So when you do this problem power to empower you multiply those experiments. So it's to the fourth power and the integral that you add one to the exploding divide by your new experiments, We have to do that from 1-2. I'm spying. So if I were doing this um you know you do have that pie To the 5th Power 248, You have 32 fists. And if you plug him 11 to that power is just itself. So you'd have 1/5. That when you subtract 32 5th minus 1/5 is 31 fist Times that pie in front. So we have 31 pi over five

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