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Find the wavelength of photons that eject 0.100-eV electrons from potassium, given that the binding energy is 2.24 eV. Are these photons visible?
530 $\mathrm{nm}$Yes, the photons are visible because the wavelength is in the visible range.
Physics 103
Chapter 29
Introduction to Quantum Physics
Quantum Physics
Cornell University
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University of Sheffield
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in this problem, we're asked to calculate the wavelength. So we are told that these electrons are These photons are ejected with 0.1 electron volts and were given that the binding energy of this metal is 2.24 All our troubles So we can say kinetic energy is our plants constant times frequency minus our work energy function. So I can first try to get frequency by itself and then I career place frequency with our speed of light is equal to three wavelength times. Frequency or speed of light, divided by wavelength equals frequency. This can also be written as planks constant times see divided by wavelength. And then I can bring wavelength up and this whole portion down and again planks constant. Here we are using 4.14 times 10 to the negative 15. Because all of our values here our intellect crumbles our speed of light. It's approximately three times 10 to the eighth meters per second and our kinetic energy was 0.1 and are binding. Energy was 2.24 This gives me a wavelength of 5.30 times 10. It's a negative seven meters, but wait for links are commonly written in nano meters, so this gives me 530 nano meters, which is inthe e visible section.
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