Find the weight on the surface of the Earth of a body whose mass is
(a) $3.00 \mathrm{~kg}$, and
(b) $200 \mathrm{~g}$.
The general relation between mass $m$ and weight $F_{W}$ is $F_{W}=m g$. In this relation, $m$ must be in kilograms, $g$ in meters per second squared, and $F_{W}$ in newtons. On Earth, $g=9.81 \mathrm{~m} / \mathrm{s} 2$. The acceleration due to gravity varies from place to place in the universe.
(a) $F_{W}=(3.00 \mathrm{~kg})\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)=29.4 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}^{2}=29.4 \mathrm{~N}$
(b) $F_{W}=(0.200 \mathrm{~kg})\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)=1.96 \mathrm{~N}$