00:01
According to the equation, we have been given f of x equals 2 multiplied by x plus 2 whole square plus 5 multiplied by x plus 2 minus of 3.
00:18
So we have been asked to find the values of x intercept for the given curve.
00:23
So how do we find the x intercept? well, the concept behind finding the x intercept that the points will have the value of y coordinate equals 0.
00:33
Now here the value of y coordinate is synonymous to f of x.
00:37
So in order to find the x in the except, we have to replace f of x with 0 and then we have to solve for x.
00:44
So let's substitute f of x equals 0, and then we have 0 equals 2 multiplied by x plus 2 whole square plus 5 multiplied by x plus 2 minus of 3.
00:58
Now in order to find the values of x, we can, what we can do is we can substitute x plus 2 equals t we are doing so because it will make our calculation a bit simple so let's rewrite our equation so it will be 2 t square plus 5 t minus of 3 equals 0 now we can write 5 t as 6 t minus of t and then we have minus of 3 equals 0 so from 2 t square plus 60 we will take 2 t common so 2 t multiplied by k plus 3 and from minus of t minus 3 we will take minus 1 common so we will have minus of 1 multiplied by t plus 3 which is equal 0 so 2 t minus 1 multiplied by t plus 3 equals 0 so when 2 t minus 1 1 equals 0 the value of t will be equals 1 upon 2 and when t plus 3 equals 0 the value of t will be equals minus of 3 but what is t is x plus 1...