00:01
So for this question, we need to find the zeros of the function algebraically.
00:05
So we're going to go ahead and use the quadratic formula that i'm going to write down right here.
00:10
And as you can see, there are three variables, a, b, and c.
00:14
So the coefficient on the x squared is going to represent our a, the coefficient on the x is going to represent our b, and then this constant is going to represent our c.
00:23
So all we really have to do is just plugging these values into the quadratic formula.
00:27
So we have negative b.
00:29
So b is 6.
00:30
So we have negative 6 plus or minus the square root of 6 squared minus 4 times a, which is 1, times negative 3, all over 2 times 1.
00:45
Because a is 1.
00:46
And we're just going to go ahead and simplify what's in that square root.
00:50
So we get 36.
00:52
And then we get negative 4 times negative 1...