Question
Find two pairs of polar coordinates, one pair with $r>0$ and the other pair with $r<0$, for the point whose Cartesian coordinates are given. In each case, choose $\theta$ so that $0 \leq m^{\circ}(\theta)<360$. $(2,-2)$
Step 1
The point is (2, -2). Step 2: Convert the Cartesian coordinates to polar coordinates using the formulas: - \( r = \sqrt{x^2 + y^2} \) - \( \theta = \tan^{-1}\left(\frac{y}{x}\right) \) Step 3: Calculate \( r \): \[ r = \sqrt{2^2 + (-2)^2} = \sqrt{4 + 4} = Show more…
Show all steps
Your feedback will help us improve your experience
Linh Vu and 99 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For each of the points given in polar coordinates, find two additional pairs of polar coordinates $(r, \theta),$ one with $r>0$ and one with $r<0$. $$(2, \pi)$$
Additional Topics in Trigonometry
Polar Coordinates
Convert to polar coordinates. Use a calculator to find $\theta$ to the nearest tenth of a degree. Keep r positive and $\theta$ between $0^{\circ}$ and $360^{\circ}.$ $$(-2,-3)$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD