Question
Find two pairs of polar coordinates, one pair with $r>0$ and the other pair with $r<0$, for the point whose Cartesian coordinates are given. In each case, choose $\theta$ so that $0 \leq m^{\circ}(\theta)<360$.$(-4,-4 \sqrt{3})$
Step 1
The Cartesian coordinates given are \((-4, -4\sqrt{3})\). Step 2: Calculate the radius \(r\) using the formula \(r = \sqrt{x^2 + y^2}\). Here, \(x = -4\) and \(y = -4\sqrt{3}\). \[ r = \sqrt{(-4)^2 + (-4\sqrt{3})^2} = \sqrt{16 + 48} = \sqrt{64} = 8 \] Step 3: Show more…
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For each of the points given in polar coordinates, find two additional pairs of polar coordinates $(r, \theta),$ one with $r>0$ and one with $r<0$. $$\left(4, \frac{3 \pi}{2}\right)$$
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List four other pairs of polar coordinates for the given point, each with a different combination of signs (that is, $r > 0, \theta > 0 ; r > 0, \theta < 0 ; r < 0, \theta > 0 ; r < 0, \theta < 0)$. $$(\sqrt{3}, 3 \pi / 4)$$
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