Question
Find two pairs of polar coordinates, one pair with $r>0$ and the other pair with $r<0$, for the point whose Cartesian coordinates are given. In each case, choose $\theta$ so that $0 \leq m^{\circ}(\theta)<360$. $(-\sqrt{3}, 1)$
Step 1
The point is \((- \sqrt{3}, 1)\). Step 2: Calculate the radius \(r\) using the formula \(r = \sqrt{x^2 + y^2}\). Here, \(x = -\sqrt{3}\) and \(y = 1\). \[ r = \sqrt{(-\sqrt{3})^2 + 1^2} = \sqrt{3 + 1} = \sqrt{4} = 2 \] Step 3: Since \(r > 0\), we can use this Show more…
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Key Concepts
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Convert each of the given pairs of rectangular coordinates to a pair of polar coordinates ( $r, \theta$ ) with $r>0$ and $0 \leq \theta<2 \pi$. $$(-\sqrt{3},-1)$$
Additional Topics in Trigonometry
Polar Coordinates
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