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Numerade Educator

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Problem 24 Easy Difficulty

Find $ y' $ and $ y". $

$ y = \frac {\ln x}{l + \ln x} $

Answer

$y^{\prime}=\frac{1}{(x)(1+\ln x)^{2}}$ and $y^{\prime \prime}=-\frac{3+\ln x}{x^{2}(1+\ln x)^{3}}$

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AO

Alex O.

June 12, 2020

it should be a 2 instead of a 3 in the numerator

Video Transcript

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