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Numerade Educator

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Problem 49 Hard Difficulty

Find $y^{\prime}$ and $y^{\prime \prime}$
$$
y=\sqrt{1-\sec t}
$$

Answer

$=\frac{\sec t\left(3 \sec ^{3} t-4 \sec ^{2} t-\sec t+2\right)}{4(1-\sec t)^{3 / 2}}$

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Video Transcript

So there is a type of here. This should be square of one minus Ah seventy and ah, So the first derivative should be by the Cheryl and we have the derivative inside here, which is our sea contention And the second the brevity we'LL use. Ah, the product rule. Certain precautions rule so that denominator squares thiss derivative off this's again Will we use for the room? So this we have sea contention times ten gin minus even killed t This's a derivative off numerator times that day nominate her and minus numerator, which is plus this times at the riveting off the denominator which is we've computed here so and you can simplify from here.