Find y^'. y=x(sin^-1 x)

Name: Problem 53, Chapter 3: Calculus, Early Transcendentals
Uploaded: 2021-07-29T01:16:18-08:00
Duration: 1 min 1 s
Channel: Tyler Moulton
Description: Find y^'. y=x(sin^-1 x)

step 1 In this problem, we wish to find the derivatives, do y, dx, for the function Y equals X, arc sin

Question

Find $y^{\prime}$. $$ y=x\left(\sin ^{-1} x\right) $$

   Find $y^{\prime}$.
$$
y=x\left(\sin ^{-1} x\right)
$$

Calculus, Early Transcendentals

Michael Sullivan,… 1st Edition

Chapter 3, Problem 53

Instant Answer

Solved by Expert Tyler Moulton

07/29/2021

Step 1

So, we have: \[y^{\prime}=x^{\prime}(\sin^{-1}x)+x(\sin^{-1}x)^{\prime}\] Show more…

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Find $y^{\prime}$. $$ y=x\left(\sin ^{-1} x\right) $$

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