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Problem 38 Medium Difficulty

Finding a Particular Solution In Exercises $37-44,$ find the particular solution of the differential equation that satisfies the initial condition(s).
$g^{\prime}(x)=4 x^{2}, g(-1)=3$

Answer

$$
\frac{4}{3} x^{3}+\frac{13}{3}
$$

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Video Transcript

So we're looking to solve the following differential equation. Do you promise that X is equal to four X squared? Well, G one sequel. The three I know that gee problem six. DX should be to your marks. This is relative for X squared. Thanks. Choose 4/3. Thanks. Cute Close some constant C. That means that ji a negative one which happens to be equal to three. Yeah, for thirds times like that one. Cute. See? Let's thank you. Parents. What scene? So that means three clothes for thirds people to see. That's nine words. Course. Full fluids. Three. Queens and Jacks. It's action just for thirds. Cute. Close. 13. Three. I hope that makes sense.