00:01
Okay, what we want to do is to find an equation of a hyperbola such that for any point on the hyperbola, the differences between the distance from two points is six.
00:15
And the two points that we're interested in is the points 10, comma, two, and 2, 2.
00:27
And also we are told, nope, and that's it.
00:36
And so since the y values are the same in the points, the transverse axis is the horizontal.
00:58
And these are the foci.
01:05
And it's because if you look at the explanation for hyperbola, the differences between the distance of the of the fosy is a constant value.
01:24
Okay.
01:25
And so those are the fosi.
01:29
And so if these are the fosi, then we also know that the fosi, then we also know that the fosi, then we also know that the fosi.
01:35
The center is exactly in the middle of those two, which makes the center six, two.
01:43
Okay.
01:44
And then also what we want to look at by definition that the distance, that distance between those two points that are actually the foci, is also twice the value of a will equal that distance as well.
02:15
And so this is in the calculus book, in the book, that says that twice the distance, and that's because the transverse axis is horizontal.
02:27
If the transverse axis was vertical, then it would be 2b is equal to that distance.
02:33
Okay...