Question
Finding an Indefinite Integral In Exercises $15-46$ , find the indefinite integral. $$\int \frac{-1}{\sqrt{1-(4 t+1)^{2}}} d t$$
Step 1
The integrand \(\frac{-1}{\sqrt{1-(4t+1)^2}}\) resembles the derivative of the inverse trigonometric function \(\arcsin(x)\), which is \(\frac{1}{\sqrt{1-x^2}}\). Show more…
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