00:01
Find the indefinite interval of one over cosine of theta minus one, d theta.
00:12
So this is kind of similar to the last case on page 519 in the book.
00:19
So let's first manipulate the integrand.
00:24
So let's take one over cosine of theta minus one.
00:31
And let's multiply it both top and bottom.
00:34
By the conjugate, which is cosine theta plus one and see what happens.
00:44
So the top just stays cosine theta plus one.
00:49
The bottom, we have cosine squared theta.
00:55
The middle terms cancel out, and the last term will be minus one.
01:00
So let's try to integrate this instead.
01:05
So we have the integral of that expression over to the right, d theta.
01:19
So we know that we have this identity that sine squared plus cosine squared is equal to one...