Question
Finding an Indefinite Integral In Exercises $15-46$ , find the indefinite integral. $$\int \frac{6}{\sqrt{10 x-x^{2}}} d x$$
Step 1
We notice that the denominator can be rewritten as a difference of squares: $$ \int \frac{6}{\sqrt{10 x-x^{2}}} d x = \int \frac{6}{\sqrt{5^2 - (x-5)^2}} dx $$ Show more…
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