We use integration by parts, where $u=x$ and $dv=\sin x dx$. The formula for integration by parts is $\int u dv = u \int dv - \int v du$.
So, we get:
\begin{align*}
\int x \sin x dx &= x (-\cos x) - \int -\cos x dx \\
&= -x \cos x + \sin x
\end{align*}
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