00:02
We're given a point and a line, and in part a, we're asked to write the equation of the line through this point in parallel to the given line.
00:11
The line is equation 5x plus 3y equals 0, and the point on the line is 7 eighths, 3 fourths.
00:46
Now, as i said in part a, we're looking for the line parallel to the given line.
00:51
In order to do this, let's write our line in slope intercept form.
00:56
So we have y is equal to negative 5x, but then divide by 3, so it's negative 5 thirds x.
01:06
From this, we see that the slope of our original line is negative 5 thirds, and therefore the slope of our new line, which is parallel to the original line, is also negative 5 thirds.
01:19
Now we have the slope of the new line and a point on it, so we'll use point slope form to write the equation of this line.
01:26
So we have y minus the y coordinate 3 fourths, over x minus the y -forknate, 3 fourths, over x minus the x coordinate 7 eighths equals the slope negative 5 thirds.
01:36
Solving for y, we have y minus 3 fourths equals negative 5 thirds x plus, and then we have 7 eighths times 5 thirds is 35, 24ths.
02:00
Solving for y, y equals negative 5 thirds x plus 35, 20 fourths plus 35 20 fourths, plus 3 fourths.
02:10
This is the same as plus 18.
02:14
Twenty -fourths...