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Finding roots with Newton's method For the given function f and initial approximation $x_{0},$ use Newton's method to approximate a root of $f .$ Stop calculating approximations when two successiveapproximations agree to five digits to the right of the decimal point after rounding. Show your work by making a table similar to that in Example 1.$$f(x)=e^{x}+x-5 ; x_{0}=1.6$$
$r \approx 1.30656$
Calculus 1 / AB
Chapter 4
Applications of the Derivative
Section 8
Newton's Method
Derivatives
Differentiation
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problem number 16 toe Approximate route are off the given function F and the initial approximation. Ex New. We used the Newton's method. The formula that we use for this is X m plus one equals xn minus fo x m over half dance off. Explain in our case F of X equals e power X Class X minus five and after dash of X, it would be our X plus one. My next note equals 1.6. We should stop calculating approximations When two successive approximations agreed to five digits toe the right off the decimal points after rounding. Now drew our table a number of iterations X men F o X and F dash of x and and X n minus. And for the Mexican my over f dash X and okay, let's use a smaller form Bigness Okay, tradition number 01 can and three Our excellent equals 1.6 and four x and 1.55 303 5.95 303 1.33912 We used this value as our next episode when 1.33912 0.15 great would win. 815 68 1.30 697 These two bodies do not agree. The four will continue for the next situation. 1.30697 0.193 4.69 496 Then this battle three, 656 These two values still do not agree toe to five digits after the decimal point. Before we continue for the Mexican situation Unlawfully, we can, uh, stop right after this. The next situation on 0.30656 0.0 Zero 006 4.69 345 and 21.30656 can see now that these two values agreed toe the five digit toe five dismount five digits after the different point before we can stop calculating our approximation.
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