00:01
So you have a jet that is flying at 500 miles per hour going due west.
00:07
So its vector, we'll call that the jet vector, would be equivalent.
00:15
Well, let's use a capital j so it doesn't look like that ij notation.
00:22
And we would have that being negative 500i, and that's plus 0j.
00:30
And the jet stream is traveling southeast at only 100.
00:37
So let's draw that in red.
00:39
And it's doing this.
00:40
So the air vector is going to end up being, we know that this is a magnitude of 100.
00:51
And so this is, this leg of this is going to end up being 100 divided by the square root of 2.
00:58
And this leg is going to have a magnitude of 100 divided by the square root of 2.
01:03
And i'm just going to leave it in that notation right now and not going to worry about simplifying it out.
01:08
I'm just going to put it like that, and you can fix that if need b.
01:11
And that's going to be positive i, and that's going to be a negative j.
01:23
And now on part b, we want to find what the vector is, the actual ground vector for this, this point.
01:33
Plane and that vector is going to be this vector.
01:38
And so we want to figure out by adding these components together.
01:42
And so now i'll add the components to give what that new velocity vector is for that plane.
01:48
So we're going to take that negative 500 and we'll add to that that 100 divided by the square root of 2.
01:58
And that comes out to be negative 429 .29 .29 .9...