00:01
So to find the inverse of this matrix, the first step is to create a matrix of minors, meaning that for each element of the matrix, we ignore the values on the current row and column, and then we calculate the determinant of the remaining values.
00:22
For example, assuming we have a matrix that looks like this.
00:34
And let's say we're working on a.
00:37
So we're just going to ignore the row and the column and calculate the determinant for the remaining value.
00:47
So in this case, it will be ei minus fh.
00:51
And you do it for the rest of the values.
00:55
And back to our problem.
01:00
In our case, we would get 3 ,201 for 4, and then 3211, and then 321, and then 3, 3 ,0, and then 2 -3 -0 -1 and then 4 3 1 1 210 and then 2 3 3 2 and then 4 3 2 and then if we calculate each of those we would end up gain 3 1 negative 3 2, 1, negative 2, and negative 2, and negative 5, negative 1, and 6.
02:12
And the next step would be the matrix of cofactors.
02:24
And all we have to do is just apply the checkerboard of minuses to the matrix of minors.
02:30
And it's going to look like this.
02:33
This is our matrix of minors, and then we just multiply that by the checkerboard meaning.
02:44
Meaning and then we would get 3 negative 1 negative 3 then negative 2 1 2 and negative 5 negative 1 then 6 and we're done with the step and the next step is it's called the adjugate, and we're going to transpose all the elements from the previous matrix by swapping the positions over the diagonal.
03:43
And what i mean by that, here is our matrix of co -factor...