Question
Finding the $n$ th Term of a Sequence In Exercises$37-48,$ write an expression for the apparent $n$ th term$\left(a_{n}\right)$ of the sequence. (Assume that $n$ begins with $1 . )$$$\frac{1}{2},-\frac{1}{4}, \frac{1}{8},-\frac{1}{16}, \ldots$$
Step 1
This suggests that we have a factor of $(-1)^n$ in our formula for $a_n$. However, we see that the first term is positive and the second term is negative, which is the opposite of what we would get with $(-1)^n$. To correct this, we add 1 to the exponent, giving Show more…
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Finding the $n$ th Term of a Sequence In Exercises $37-48,$ write an expression for the apparent $n$ th term $\left(a_{n}\right)$ of the sequence. (Assume that $n$ begins with $1 . )$ $$ 1, \frac{1}{4}, \frac{1}{9}, \frac{1}{16}, \frac{1}{25}, \dots $$
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Finding the $n$ th Term of a Sequence In Exercises $37-48,$ write an expression for the apparent $n$ th term $\left(a_{n}\right)$ of the sequence. (Assume that $n$ begins with $1 . )$ $$ 1+\frac{1}{2}, 1+\frac{3}{4}, 1+\frac{7}{8}, 1+\frac{15}{16}, 1+\frac{31}{32}, \ldots $$
Write an expression for the apparent $n$ th term of the sequence. (Assume $n$ begins with $1 .$) $$\frac{1}{2}, \frac{-1}{4}, \frac{1}{8}, \frac{-1}{16}, \dots$$
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