00:01
So in the given question we have to deal with two forms of equations, one of which is the point slop form.
00:11
So here this form represents a line which passes through the point x1 y1 and has a slop equal to m.
00:24
So the equation is y minus y1 is equal to m times x minus x1.
00:31
So this is the point slop form.
00:35
Now next we have the slop intercept form, right? so the slop intercept form represents a line with slop, say, m.
00:56
And if the line cuts the y -axis at b, then we can say that the y -inderset of the line.
01:05
Line is equal to b and such a line is represented by the equation y equals mx plus b which is the slop in the such form so now we have a line that passes through the point minus 6 1 and 2 minus 5 so we can write using the point slop form an equation using the first point minus 6 1.
01:42
So then we can write y minus 1 equals the slope is unknown so let's write m as the so m times x minus minus 6 which is y minus 1 equals m times x x plus 6.
02:02
So we can expand this and write as y minus 1 equals m times x plus 6 times m and y would be equal to mx plus 6m plus 1.
02:20
So let's take this as the first equation.
02:24
Now let's take the second point which is 2 minus 5.
02:30
So we can write using the points law form y minus minus 5 equals m times x minus 2...