00:01
Hi guys, this problem is to find the parabola that passes the point 0, 3, 3, 4, and 411.
00:13
Okay, and the axis of this problem will be parallel to the y -axis.
00:26
So parallel to y -axis.
00:32
So we know for the problem that the problem that has the axis parallel to y -axis, the equation must be y equals to the quadratic function of x.
00:49
Okay, so it's something like this.
00:53
So then we can plug those three points to this equation.
00:58
Plug 0 -3 to this equation.
01:04
We get 3 equals to 0 plus 0 plus c.
01:12
So plug in 3 -4 to this equation.
01:17
We get 4 equals to 3 square a, so it's 9a, plus 3b plus c.
01:28
And then we plug the 4 -11 to this equation.
01:35
We get 11 equals to a times 4 square, which is actually 16, plus bx, so it's 4b, plus c.
01:47
Okay, so from the first equation we get c equals to three.
01:53
So we can plug the c, plug three to c for the next two equations.
02:02
Okay, so it's four equals to nine a plus three b plus three.
02:09
Okay, and here 11 equals to 16 a plus 4b plus three.
02:16
Okay, so we can see that is 9a plus 3b equals to 1...