00:01
In this problem, we're given a series of ln of n over n to the power p.
00:09
We're given that n is equal to 2 and the upper bound limit of affinity.
00:18
So consider the function f of x, f of x is equal to ln of x over x to the p.
00:39
We know that this function has to be positive, continuous, and by graphing it, in your graph and calculator, you would see that the values are positive and decrease in when x is greater than all equal to 2 for any positive values of p.
01:11
Because of that, we now apply the integral test.
01:17
So applying the integral test, we have 2 in infinity, f of x, dx, which is equal to f of x is l .m of x.
01:44
Over x to the p d x the x the integral of l and of x of p is one over two ellen of x squared and because there's a limit so the limit as b approaches infinity of one of two ellen of x squared were bounds to and b if you input that to your calculator you have one over two 1 over 2 times ln of 2 squared minus ln of infinity squared...