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Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to truthfully report the mass).(a) What is the force constant of the spring in such a scale if it the spring stretches 8.00 $\mathrm{cm}$ for a 10.0 kg load?(b) What is the mass of a fish that stretches the spring 5.50 $\mathrm{cm} ?$(c) How far apart are the half-kilogram marks on the scale?

$\begin{aligned} K &=1225 \mathrm{N} / \mathrm{m} \\ m &=6.875 \mathrm{kg} \\ x_{c} &=0.0004 \mathrm{m} \end{aligned}$

Physics 101 Mechanics

Physics 103

Chapter 16

Oscillatory Motion and Waves

Periodic Motion

Wave Optics

Cornell University

Rutgers, The State University of New Jersey

University of Washington

Hope College

Lectures

02:51

In physics, wave optics is the study of the behavior of light, or other electromagnetic waves, as they interact with matter. It is a branch of classical optics. While the term "optics" usually refers to the study of light propagation in free space, "wave optics" is used when it is important to take into account the effects of the material the light is traveling through. Wave optics is mostly concerned with the behavior of waves near the boundary between different media. When waves from a single source interact with each other their behavior can be difficult to predict. For example, two waves of the same frequency and wavelength can interfere, leading to a phenomenon known as interference fringes.

10:02

Interference is a phenomenon in which two waves superpose to form a resultant wave of greater, lower, or the same amplitude. Interference effects can be observed with all types of waves, including water waves, sound waves, and light. If a crest of a wave meets a crest of another wave of the same frequency at the same point, then the amplitude is increased. If a crest of one wave meets a trough of another wave, then the amplitude is decreased. Interference can also refer to the interaction of acoustic waves in the cochlea of the inner ear.

03:20

Fish are hung on a spring …

08:13

02:08

You have a mechanical fish…

01:52

01:22

A scale used to weigh fish…

02:11

$\bullet$ A proud deep-sea…

03:43

If a fish is attached to a…

02:05

A fish scale, consisting o…

03:52

A proud deep-sea fisherman…

03:38

Spring scale $A$ is attach…

so to find the value off spring costume K, we are going to use hooks Law F is equal to negative cakes. In this case, we don't care about this negative sign because all we need in this case is the magnitude on we arguing that fish off 10 kilogram is attached to the spring. So we are going to equate host you to gravity to K X. And from this we can find K s m j divided by ex. So I assumed that the spring is like this on Lord is attached to this hook here which weighs about 10 kilograms. So this will be the fools acting downwards. And this will be the fools acting upwards which is for this course. This is gravitational force. This is springs force. So let's substitute all the values capable to 10 times 9.8 divided by the displacement which is eight centimeters, 0.8 meters c. I kept value in meters so answer here is 1 to 25 Newton who meter in part B. We are asked how much master will stretch the string. Bye bye point Fight again. We will use the same formula omg is equal to K X and in this case we are given X being okay. We are supposed to find the value of mass. So mass is equal to 12 to 5 time still value effects, which is 5.5 centimeters, 0.55055 divided by 9.8. So if you do this, you will get six point 875 kills on in the party. We are asked how How far apart are half kilogram marks on the scale? So let's find out X for half kilogram. So we know masses half kilogram times 9.8, divided by 12 to fight. This gives you the answer. Zero points use you for Meet us, I think.

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