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Fish biomass The rate of growth of a fish population was modeled by the equation $$G(t)=\frac{60,000 e^{-0.6 t}}{\left(1+5 e^{-0.6 t}\right)^{2}}$$ where $t$ is measured in years since 2000 and $G$ in kilograms per year. If the biomass was $25,000 \mathrm{kg}$ in the year $2000,$ what is the predicted biomass for the year 2020$?$
$25,000 \mathrm{kg}$
Calculus 1 / AB
Calculus 2 / BC
Chapter 5
Integrals
Section 4
The Substitution Rule
Integration Techniques
Campbell University
Harvey Mudd College
University of Michigan - Ann Arbor
Boston College
Lectures
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so for this question were given the GFT is equal to 120,000 e to the power of native of 0.60 and this is divided by one plus five e to the power of negative 0.60 square where t is measured in years since 2000. And Jean kill is the kilograms for a year if the biomass was 25,000 in the year 2000. So basically, we have to take the integral of this, uh, to get that this is equal to, uh, this is equal to 60,000 e to the power of one point for tea plus C then used the initial condition. But when TZ holds zero G is equal to 25,000 on, then we predict the master 20 twenties when we fired AT T is equal to 10
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