00:01
In this case, we have a circuit that looks like this.
00:06
Three circuits in three resistors in parallel, connected to a power source.
00:12
And the resistances are 4 .8 om, 2 .4 oom, and 1 .2 om.
00:25
And the voltage is 2 .8 volt.
00:31
Let's call this resistor 1, resistor 2, and resistor 3.
00:35
And the voltages across them and the currents across them will be v1, v2, v3, and i1, i2, i3.
00:41
Now we want to find out the net resistance because these three are in parallel, we know that the net resistance can be found out using this formula.
00:52
I'm sorry, this is 1 .60, 1 .6 plus 1 by 1 .24 plus 1 by 1 .4, 1 by 4 .8 which gives us the resistance is 0 .8.
01:05
O.
01:08
This is part a.
01:10
For part b, we want to find out the current through each of these resistors.
01:18
For that, we simply do the current through the first resistor is the voltage divided by the r1.
01:24
Because the voltage, as you can see, is the same in all three cases.
01:29
They share these terminals and hence the voltage across all of them is equal to 2 .8 volt.
01:37
So the current through the first one is simply 2 .8 by 1 .6 which gives us i'm sorry this is 28 volt which gives us 28 17 .5 ampere and i2 is simply v by r2 which is 2 .8 by 2 .4 i'm sorry 28 by 2 .4 which is 11 .7 amper and i3 similarly is 28 volt divided by 4 .8 oom which is 5 .8 amper.
02:16
Now for part c we want to find out the total current...