Fluoromethane $\left(\mathrm{CH}_{3} \mathrm{~F}, \mu=1.81 \mathrm{D}\right)$ has a smaller dipole moment than chloromethane $\left(\mathrm{CH}_{3} \mathrm{Cl}, \mu=1.87 \mathrm{D}\right)$ even though fluorine is more electronegative than chlorine. Explain.