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Flux across curves in a flow field Consider the flow field $\mathbf{F}=\langle y, x\rangle$ shown in the figure.a. Compute the outward flux across the quarter circle $C: \mathbf{r}(t)=\langle 2 \cos t, 2 \sin t\rangle,$ for $0 \leq t \leq \pi / 2$b. Compute the outward flux across the quarter circle $C: \mathbf{r}(t)=\langle 2 \cos t, 2 \sin t\rangle,$ for $\pi / 2 \leq t \leq \pi$c. Explain why the flux across the quarter circle in the third quadrant equals the flux computed in part (a).d. Explain why the flux across the quarter circle in the fourth quadrant equals the flux computed in part (b).e. What is the outward flux across the full circle?(FIGURE CAN'T COPY)
A. 4B. $$-4$$ C. identical D. identical E. 0
Calculus 3
Chapter 15
Vector Calculus
Section 2
Line Integrals
Vectors
Oregon State University
Harvey Mudd College
University of Michigan - Ann Arbor
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Our Prime 66 given F. Is why comma X. Compute outward flux for R. F. G. Equal to two. Co sign T. two sci fi. Mhm. From zero two Pi over two. So gradient is defined. Bye partial respect to X. Partial with respect to Y partial or the spec to see. So for a R. T. is to co sign TO two. Sine of T. Our prime FT. Good negative too Sine of T. To co sign T. The integral. EFTa. And yes Go to integral from zero. Hi over to of to scientific comma negative two eco sci fi ah two co scientific comma negative two Sine T. D. T. That equals in a girl from zero to pi over two for scientology. Cose I inti Plus four. Sine T. Cose I inti T. T. Or in a girlfriend pie overseas in trig identities of sign to T. T. T. Take the integral. Got four. It's negative. Co sign to T. Over two, Evaluated from Pi over 220. That gives us four. All right party new privatization of our to co sai inti to sign T. Our prime FT. To go negative too sci fi. Two eco sci fi integral would be integral From pi over two hi of to sign T comma negative to co sign T. Ah To co sai Inti Come on a -2. Sine of T G. T. Now again this is gonna equal to pi over 22 pi a sign T. Co. Sine T DT which is you go to four cents in the grove power teared up. I signed to T T. T. The integral simplifies two negative coastline to T. Over two evaluated however, to two pi Which is -4. So that's where fox is negative for parsi. Since the vector field F. In the normal vector and the first of the quadrants are negative. The flux is the same. So the flux is identical flux. Ah I tend to call and first and third quadrant party since F. And the normal vector and the second quadrant Um is negative as is in the 4th quadrant. Their product is the same. So flux is identical in second and four step E. Our flux is the combined flux across each quadrant. So net Does he go to 4 -4 plus 4 -4 Which is equal to zero.
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