Now, let's consider two different launch angles, $\theta_1$ and $\theta_2$, that result in the same range. According to the formula, we have:
$\frac{v^2 \sin(2\theta_1)}{g} = \frac{v^2 \sin(2\theta_2)}{g}$
Since $v$ and $g$ are constants, we can simplify this
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