00:01
This problem, lambda, is 10 ,000.
00:05
For problem a, the probability that x is greater than 20 ,000 is the probability that a normal distribution variable that is, so we have 2 ,000, so plus 0 .5 minus 10 ,000, square of 10 ,000.
00:30
So we can guess this is a pretty large number, approximately 100.
00:36
So this is too large that the probability is almost 1.
00:43
For problem b, probability that x is more than 9 ,900 is equal to a random variable, has normal distribution.
00:57
So it's more than this part over squared of 10 ,000.
01:05
And the probability is that they are equal than negative 1 .005.
01:10
0 .05, and this probability is 0 .157.
01:17
And for problem c, we have that the suppose the variable one that calculates its name as t.
01:25
So we got this probability that greater equal than t plus .5 minus sorry, 10 ,000 over 10 ,000 is .01.
01:47
Then we can calculate the fact that t plus 0 .5 minus 10 ,000 overscarer of 10 ,000.
02:00
So using this fact, so this is the critical value 1...