00:01
In this question, we are going to focus on finding out the value of d brogley wavelength as well as we need to compare the d brogley wavelengths of electron.
00:09
So firstly in the first part we can write that the value of momentum is here given to be equal to 5 .7 multiplied with 10 raised to the power negative 26 and then here it will be kg and then we can say meter per second.
00:24
So now it can be here written that the value of wavelength is equal to h divided with p.
00:30
And hence we can say that since the value of momentum, let us here write that since the electron and it will be here proton, both have equal momentum, so it can be here written that both have equal and then it will be here momentum.
00:51
So here p denotes momentum and hence since they have equal momentum, that means we can here right that the value of d brogley wavelength will also be equal because h is nothing but plank constant.
01:03
So plank constant has a fixed value and hence we are left with only the momentum value.
01:08
That if the value of momentum changes then the value of wavelength will change.
01:12
Otherwise the wavelength will remain same.
01:15
Hence here we can say that the value of wavelength basically for proton as well as for we can here say it will be so pr denotes proton and here electrons...