For a Si photoconductor of length $5 \mu \mathrm{m}$, doped $\mathrm{n}$ -type at $10^{15} \mathrm{~cm}^{-3}$, calculate the change in current density when we shine light on the photoconductor under the following circumstances: We create $10^{20}$ electron-hole pairs $/ \mathrm{cm}^{3}-\mathrm{s}$ and carrier-recombination lifetimes, $\tau=0.1 \mu$ s. The applied voltage is $2.5 \mathrm{~V}$ across the photoconductor's length. How about if we increase the voltage to $2500 \mathrm{~V} ?$ The electron and hole mobilities are $1500 \mathrm{~cm}^{2} / \mathrm{V}-\mathrm{s}$ and $500 \mathrm{~cm}^{2} / \mathrm{V}-\mathrm{s}$,
respectively, in the ohmic region for electric fields below $10^{4} \mathrm{~V} / \mathrm{cm}$. For higher fields, electrons and holes have a saturation velocity of $10^{7} \mathrm{~cm} / \mathrm{s}$.