Question
For a temperature difference $\Delta T=20.0^{\circ} \mathrm{C},$ one slab of material conducts $10.0 \mathrm{W} / \mathrm{m}^{2} ;$ another of the same shape conducts $20.0 \mathrm{W} / \mathrm{m}^{2} .$ What is the rate of heat flow per $\mathrm{m}^{2}$ of surface area when the slabs are placed side by side with $\Delta T_{\mathrm{tot}}=20.0^{\circ} \mathrm{C} ?$ (FIGURE CAN'T COPY)
Step 1
0 \, \mathrm{W/m^2}$. We can write this as $P_1 = \Delta T / R_1$, where $R_1$ is the thermal resistance of the first slab and $\Delta T = 20.0^{\circ} \mathrm{C}$. Solving for $R_1$ gives us $R_1 = \Delta T / P_1 = 20.0 \, \mathrm{K/W}$. Show more…
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For a temperature difference $\Delta T=20.0^{\circ} \mathrm{C},$ one slab of material conducts $10.0 \mathrm{W} / \mathrm{m}^{2} ;$ another of the same shape conducts $20.0 \mathrm{W} / \mathrm{m}^{2} .$ What is the rate of heat flow per square meter of surface area when the slabs are placed side by side with $\Delta T_{\mathrm{tot}}=20.0^{\circ} \mathrm{C} ?$
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