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This is the answer to chapter 12 problem number 36 from the smith organic chemistry textbook.
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And this problem is giving us three alkenes and then asking us a series of questions about these alkenes.
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And so i've drawn them here, a, b, and c.
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And so first we're asked to rank them from lowest heat of hydrogenation to highest heat of hydrogenation.
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And so remember, this question is really asking us about the stability of these alkenes.
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And so in order to determine that, we look at the substitution pattern.
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We see that a is mono substituted, b is tetra substituted, and c is tri -substituted.
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And so based on that, we can make a pretty easy judgment.
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B is going to be the most stable because it's tetras substituted, and therefore it's going to have the lowest heat of hydrogenation.
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C, tri -substituted, is going to be slightly less stable than b.
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So its heat of hydrogenation will be slightly higher.
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And then a, mono -substituted is going to be significantly less stable than b or c, and so it will have the highest heat of hydrogenation.
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So for part b of this question, we're asked to rank the same three molecules by their rate of reaction with h2 and palladium on carbon.
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So how quickly they would be hydrogenated.
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And so really, this is just another way of phrasing the same question we were asking part a.
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So the least stable molecule, the molecule that gives off the most energy when it is hydrogenated, is also going to be the most eager to be hydrogenated...