For an electron in a 3$d$ state, determine (a) the principle quantum number and (b) the orbital quantum number. (c) How many different magnetic quantum numbers are possible for an electron in that state?
Answer not available
in this exercise, we have an election in the three de ST. And in question eight, we have to determine the principal Quintal number. And that's just the end that characterizes the energy level. In this case, we have a and pickles three. Okay, because remember that, uh, in the convention for riding the state of the electron, we have that be right. And the Facebook wants a number. And then l okay. And now is the orbital Quintal number for be. We have to find What is the the orbitofrontal number off the electric. So here, have that l is equal to D. Okay, now what is D? What does d represent? So we have that for l equals zero. The corresponding ladder is s for l equals one. The corresponding ladder is p for Allah. Close to the corresponding letter is D. So this means that the orbital frontal number in this case is to okay and in questions. See, we have to say how many different possible magnetic quantum numbers are. There are for this magnetic mental number that I'm sorry for this article, Quintal number l equals to that. I just found in question. Be well remember that the medic magnetic quantum number can have that is starting at minus l up until l. So the number of possible magnetic quintal numbers given an orbit of one. The number l is to help us one. Okay, this is the number that I'm gonna call Capital. And in our case, since l equals sue, capital N equals fine. So there are five possible magnetic quantum numbers.