00:01
Alright, so for this problem we are given the equation for using a thin lens.
00:09
Right now we see that this equation is in this form, and we want to write the equation that it is solved for the object distance or d of 0.
00:22
So, in order to do this, i'm going to get rid of my fractions by multiplying everything by the least common multiple, which i'm going to find by multiplying everything, all of the denominators together.
00:43
So my least common multiple is going to be f times d of 0 times d of i.
00:51
So i'm going to multiply this whole equation by that least common multiple.
00:56
So i'm going to get that that least common multiple is going to be on the top of all of my fractions.
01:04
So i'm going to rewrite this as f of my least common multiple over f is equal to my least common multiple over d of 0 plus my least common multiple over d of i.
01:21
Now i see that for each of these, something is going to cancel out.
01:25
My f's cancel out here, my d of 0's cancel out here, and my d of i's cancel out here.
01:33
So i'm left with d of 0 d of i is equal to f of d of i plus f of d of 0...