00:01
Okay, what we want to do is we want to walk through a proof, and what we want to prove is that if we are told that the limit of f of x as x goes to infinity is equal to some numerical value, and the limit as x goes to infinity of g of x is equal to another numerical value, then the limit as x goes to infinity of f of x plus g of x has to equal a plus b.
00:26
And so this proof is going to be very similarly similar to ones that maybe you have done in a previous section based off of that epsilon delta definition of a limit.
00:39
And we're going to actually use kind of that same scenario of a proof in combination with the definition of limits as x goes to positive infinity.
00:56
And so what we're going to do is we're going to let, you know, epsilon, of course, be greater than zero.
01:07
And since we know, and we're going to stick with this first limit first, since we know that the limit as x goes to infinity of f of x is equal to a, then, of course, there is a.
01:31
Corresponding number and and typically we would say capital m but we're going to have to define them since we have two limits we're going to do that as m1 such that x is greater than m1 is going to imply that f of x minus a is equal to epsilon over two and of course we're going to do epsilon over two and not epsilon because we have combining multiple limits.
02:07
Okay.
02:08
So this is just kind of like that definition of limits as x goes to positive infinity.
02:15
And then we're going to similarly do the same thing for the limit as g of x as well.
02:21
So this one we're going to let epsilon be greater than zero.
02:27
And since the limit as x goes to infinity of g of x is equal to b, then there is a number, a corresponding number, excuse me.
02:47
Because we need to keep consistent...