The vector $a+b$ is given by $(1+0, 3+3, -2+1) = (1,6,-1)$. Now, we calculate the cross product of $(a+b)$ and $c$:
$$(a+b) \times c = (1,6,-1) \times (0,-1,2) = (6 \cdot 2 - (-1) \cdot (-1))\mathbf{i} - (1 \cdot 2 - (-1) \cdot 0)\mathbf{j} + (1 \cdot (-1) - 6
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