We can do this by substituting different values of $x$ into the equation and solving for $y$.
For $x=-3$, we have $y=|-3-2|=5$. So, $(-3,5)$ is a solution.
For $x=1$, we have $y=|1-2|=1$. So, $(1,1)$ is a solution.
For $x=3$, we have $y=|3-2|=1$. So, $(3,1)$ is
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