Question
For each $l$ value, the number of possible states is $2(2 l+1) .$ Show explicitly that the total number of states for each principal quantum number is $\sum_{l=0}^{n-1} 2(2 l+1)=2 n^{2}$ This gives the degeneracy of each energy level.
Step 1
Step 1: We start with the given sum: \[\sum_{l=0}^{n-1} 2(2 l+1)\] Show more…
Show all steps
Your feedback will help us improve your experience
Suzanne W. and 94 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For each $l$ value, the number of possible states is $2(2 l+1)$. Show explicitly that the total number of states for each principal quantum number is $\sum_{l=0}^{n-1} 2(2 l+1)=2 n^{2} .$ This gives the degeneracy of each energy level.
Each quantum state of the hydrogen atom is labeled by a set of four quantum numbers: $\left\{n, \ell, m_{\ell}, m_{s}\right\}$ (a) List the sets of quantum numbers for the hydrogen atom having $n=1, n=2,$ and $n=3$ (b) Show that the degeneracy of energy level $n$ is $2 n^{2}$
Each quantum state of the hydrogen atom is labeled by a set of four quantum numbers: {n, ℓ, mℓ, ms}. (a) List the sets of quantum numbers for the hydrogen atom having n = 1, n = 2, and n = 3. (b) Show that the degeneracy of energy level n is 2n².
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD