Question
For each of the following: $(14.2,14.3)$1. $\mathrm{HNO}_{3}$2. HFa. Write the formula for the conjugate base.b. Write the $K_{\mathrm{a}}$ expression.c. Which is the weaker acid?
Step 1
Therefore, the conjugate base of $\mathrm{HNO}_{3}$ is $\mathrm{NO}_{3}^{-}$ and the conjugate base of HF is F$^{-}$. Show more…
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