00:02
This is the answer to chapter 14, problem number 41 from the zoomdahl chemistry textbook.
00:10
This problem gives us three equations, three acid base equations, and we're asked to identify the acid, the base, the conjugate base, and the conjugate acid.
00:22
And so we can do this just based on the definitions.
00:26
So the acid is going to be what donates the proton.
00:30
The base will be what accepts the proton, and then the conjugate acid will be what the base becomes on the other side of the reaction, basically, and the conjugate acid will be what the base becomes on the other side of the reaction.
00:52
So for a, we have h2o is going to become h3o plus.
01:01
So the h2o is accepting a proton, so that is going to make it the base, which makes the h2 -co3, the carbonic acid, the acid.
01:15
And then so the h3o plus is going to be the conjugate acid, and that will make the h -c -o -3 minus the conjugate base.
01:37
And i'm going to just abbreviate conjugate with just con i guess okay and so we'll follow that pattern so looking at part b we have c5h5 and h plus and water and so what we can see is that again water is going to be accepting the proton and so that is going to make water the base.
02:10
The species donating the proton is going to be the acid...